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Re: How to enumerate files in a directory using the builtin shell?

From: Jordan Uggla
Subject: Re: How to enumerate files in a directory using the builtin shell?
Date: Thu, 28 Jan 2016 21:54:09 -0800

On Thu, Jan 28, 2016 at 5:56 PM, Thiago Padilha <address@hidden> wrote:
> I want to execute one "menuentry" command for each file in a directory.
> What's the best way to do it? In bash I would use something like `for file
> in $(ls); do`, but can't seem to find a way to use grub's `for` command.

You shouldn't try to parse the output of ls, even in bash:

For both grub and bash, to iterate over files you should use a for
loop with globs. The difference with grub being that you need to first
"insmod regexp" to enable globbing, for example:

insmod regexp # This is grub specific

# The following lines work exactly the same in bash and grub
for file in /boot-isos/*.iso; do
  echo found iso file "$file"

For a more complete real world example, the following grub script will
search for all files, on all devices/partitions, in a directory named
"/boot-isos/" and ending in ".iso" and will assume that they have a
loopback.cfg ( ). For
each iso found it will create an appropriate menuentry for booting the
iso using the loopback.cfg found within that iso:

insmod regexp
insmod all_video

for iso_with_device in (*)/boot-isos/*.iso; do

  # Remove the grub device name to get just the path to the iso
relative to its root.
  regexp --set=iso_path '^\(.*\)(.*$)' "$iso_with_device"

  menuentry "loop boot $iso_with_device" "$iso_path" {
    export iso_path
    search --set=root --file "$iso_path"
    loopback loop "$iso_path"
    configfile /boot/grub/loopback.cfg
    loopback --delete loop

Jordan Uggla (Jordan_U on

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