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Grub1.99 error on start
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From: |
J E Garrott Sr |
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Subject: |
Grub1.99 error on start |
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Date: |
Fri, 20 May 2011 17:42:57 -0700 |
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User-agent: |
Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.2.17) Gecko/20110501 Thunderbird/3.1.10 |
grub seems to work fine, but just before the menu comes up,
this message appears:
"error:(hd0, msdos1)/usr/share/grub/generic.tga:2:205
missing seperator after property name I' _"
It doesn't seem to relate to anything in the start
scripts in /etc/grub.d. I am not an accomplished
programmer, so I am asking if anyone knows how
to get rid of it.
Thanks, John
- Grub1.99 error on start,
J E Garrott Sr <=