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Re: function pointer

From: Ali
Subject: Re: function pointer
Date: Thu, 21 Aug 2008 18:19:23 -0700 (PDT)
User-agent: G2/1.0

On Aug 21, 11:16 pm, Thomas Maeder <> wrote:
> Ali <> writes:
> > The documentation of the interval class is here:
> Please post a minimal (i.e. just enough code, not more and not less)
> that allows others to copy & paste & compile & see what you are seeing.

Quite unfortunately all my minimal codes compile and run without any
problems with g++ (with MS VS2005 i get: error C2440: '=' : cannot
convert from 'foo (__cdecl *)(const foo &)' to 'foo (__cdecl *)(const
foo &)'
Incompatible calling conventions for UDT return value), it is strange
that with the original code VS2005 work properly). Please see the
minimal code at the end of this message.

I do not understand the original error message:

main.cpp:9: error: no matches converting function ‘operator+’ to type
‘class cxsc::interval (*)(const class cxsc::interval&, const class
candidates are: cxsc::interval cxsc::operator+(const cxsc::interval&,
const cxsc::interval&)

What is the compiler's problem? What is the different between my
declaration and the candidate?

Let me emphasize that the minimal code below compiles with g++. I also
tried to encapsulate the class into a namespace but still worked.


class foo {


        friend foo operator+(const foo&, const foo&);

        friend foo operator-(const foo& );

foo operator+(const foo&, const foo&) {

        return foo();

foo operator-(const foo&) {

        return foo();

int main() {

        foo (*Add) (const foo&, const foo&);

        Add = operator+;

        foo (*Neg) (const foo& );

        Neg = operator-;

        return 0;

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