Re: Passing multiple arguments to makefile

[Henrik Carlqvist]

Duke Normandin <dukeofperl@ml1.net> wrote:
> I want to do the following:
> 
> `make ARGS= "exec_file src_1 src_2 etc"'
> 
> I realize that $(ARGS) will contain _all_ the arguments. I need to
> come up with a way to split out each argument to get to:
> 
> EXEC-FILE = exec_file
> SRCS = src_1 src_2 src_3

Then why not simply do:

make EXEC-FILE=exec_file SRCS="src_1 src_2 src_3"

But if you really want to use your syntax you could also do:

EXEC-FILE= $(word 1, $(ARGS))
SRCS = $(wordlist 2, 999, $(ARGS))
 
> I'm trying to create a "generic" makefile for a non-C compiler. Is
> this possible? TIA...

Of course it is possible to do other things than compiling C code. Make
simply tries to create files when it finds that some other files are newer.
This creation of files could be done by running a C compiler, but it could
also be done with any other tool of your choice.

regards Henrik
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