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Re: Question about parse-time-string and date-to-time


From: John Mastro
Subject: Re: Question about parse-time-string and date-to-time
Date: Wed, 29 Mar 2017 15:14:18 -0700

Eric Abrahamsen <address@hidden> wrote:
> A conundrum:
>
> parse-time-string accepts a string representing a date, and parses it
> into a list of time elements, with nil for the unknowns.
>
> date-to-time calls parse-time-string and passes the result straight to
> encode-time, to produce a time value.
>
> encode-time accepts series of time elements, and raises an error if any
> of them are nil.
>
> I might be missing something, but I don't see how date-to-time could
> ever work. Wouldn't it always have to replace the nils with zeros before
> passing the result to encode time?

It looks like, if the first call to `encode-time' signals an error, it
re-tries using the result of calling `timezone-make-date-arpa-standard'
on the original DATE argument:

    (defun date-to-time (date)
      (condition-case err
          (apply 'encode-time (parse-time-string date))
        (error
         ;; ...
         (apply 'encode-time
                (parse-time-string
                 (timezone-make-date-arpa-standard date)))
         ;; ...
         )))

I was not familiar with `timezone-make-date-arpa-standard', and am not
familiar with "arpanet standard date" as a concept. It seems to
guarantee that some valid date string will be returned, but not
necessarily the one I would have guessed when time information is
missing:

    (timezone-make-date-arpa-standard "2017-03-29 3:05:00")
    ;=> "28 Mar 2017 20:05:00 -0700"
    (timezone-make-date-arpa-standard "2017-03-29")
    ;=> "31 Dec 1999 16:00:00 -0800"
    (timezone-make-date-arpa-standard "3/29/2016")
    ;=> "31 Dec 1999 16:00:00 -0800"

And sure enough:

    (equal (date-to-time "2017-03-29")
           (date-to-time "31 Dec 1999 16:00:00 -0800"))
    ;=> t

So it seems like it returns an arbitrary date if time elements are
missing?

        John



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