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The two-argument form of defvar

From: Philipp Stephani
Subject: The two-argument form of defvar
Date: Thu, 19 Mar 2015 11:39:48 +0000


when looking at the source code of defvar it becomes clear that the
two-argument form

(defvar foo)

is a no-op. It is often used as a signal to the byte compiler that a
certain variable will be available, similar to declare-function. Would it
be possible to clarify the docstring accordingly? Currently it has no
indication that the two-argument form doesn't do anything.

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