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Re: print out all members of a list, v.1.0
From: |
Pascal J. Bourguignon |
Subject: |
Re: print out all members of a list, v.1.0 |
Date: |
Fri, 04 Mar 2011 11:39:23 +0100 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/23.2 (gnu/linux) |
Barry Margolin <barmar@alum.mit.edu> writes:
> Emacs Lisp is mostly a reimplementation of MockLisp, the dialect that
> was used in Gosling Emacs, which was the original inspiration for GNU
> Emacs. It's also very much like MACLISP, the dialect that RMS had been
> using for over a decade.
>
> So he didn't design his own language, he was basically sticking with
> what he knew and liked.
MacLisp probably. CL is inspired a lot from MacLisp too. But I've
read that MockLisp was far from being a full lisp (as its name would
imply), and that it was probably the reason why RMS had to write a new
real lisp for his emacs.
--
__Pascal Bourguignon__ http://www.informatimago.com/
A bad day in () is better than a good day in {}.
- Re: print out all members of a list, v.1.0, (continued)
- Re: print out all members of a list, v.1.0, rusi, 2011/03/01
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/02
- Re: print out all members of a list, v.1.0, rusi, 2011/03/02
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/02
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/02
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/03
- Re: print out all members of a list, v.1.0, rusi, 2011/03/03
- Re: print out all members of a list, v.1.0, Pascal J. Bourguignon, 2011/03/03
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/03
- RE: print out all members of a list, v.1.0, Drew Adams, 2011/03/03
- Re: print out all members of a list, v.1.0,
Pascal J. Bourguignon <=
- Re: print out all members of a list, v.1.0, David Kastrup, 2011/03/04
- Re: print out all members of a list, v.1.0, Barry Margolin, 2011/03/04