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print out all members of a list

From: ken
Subject: print out all members of a list
Date: Mon, 28 Feb 2011 10:20:20 -0500
User-agent: Thunderbird (X11/20101213)

(car '("one" "two" "three"))

prints out "one" ... the first of the list.  How to print out all
elements of the list (in order and with the double quotes around them?
I'm actually looking just to substitute something for "car" and not
write an entire function.  Or is there no such thing?

Thanks much.

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