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Re: How to convert a char to a property
From: |
Cecil Westerhof |
Subject: |
Re: How to convert a char to a property |
Date: |
Wed, 08 Dec 2010 15:21:15 -0000 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/23.1 (gnu/linux) |
Op dinsdag 27 jul 2010 10:29 CEST schreef Cecil Westerhof:
> I have the following property list:
> (defvar dcbl-bbdb-user-defined-fields (list :L "mail-alias"
> :M "mailer"
> :P "playlist"
> :s "subjects"
> :t "type"
> :w "website")
> "User defined fields in the bbdb with parameter to insert into buffer")
>
> With (getf dcbl-bbdb-user-defined-fields :M) I get "mailer".
>
> But I want to work parameter driven. So for example I have:
> (setq parameters "MLst")
> (setq current-char (string-to-char parameters))
>
> The variable current-char now contains 77. How could I use
> current-char to retrieve "mailer"?
At the moment I use another solution.
I now have:
(defvar dcbl-bbdb-user-defined-fields '(("L" "mail-alias")
("M" "mailer")
("P" "playlist")
("s" "subjects")
("t" "type")
("w" "website"))
"User defined fields in the bbdb with parameter to insert into buffer")
and use the following code:
(setq field-name nil
parameters dcbl-bbdb-user-defined-fields
this-value nil)
(while parameters
(setq this-parameter (car parameters)
parameters (cdr parameters))
(when (string= current-char (car this-parameter))
(setq field-name (car (cdr this-parameter))
parameters nil)))
The variable current-char is the parameter (as a string) that I am
searching for.
This does work, but I do not know if it is very efficient. Is this a
good solution, or should I code it differently?
--
Cecil Westerhof
Senior Software Engineer
LinkedIn: http://www.linkedin.com/in/cecilwesterhof