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statement with no effect
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From: |
Anouar LACHHEB |
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Subject: |
statement with no effect |
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Date: |
Wed, 1 Mar 2006 12:34:34 +0100 |
Hi,
I compiled
my ".lex.c" file with GNU gcc v 3.4.5 and I get this
warning:
/work/Diagnostic/YieldTracker/Parser_Module/CYC_SPLIT/Integration/ParserModuleC.l:61:
warning: statement with no effect.
The line number 61 corresponds to "%%" in the
".lex" source file.
I want to
know first, why I got that warning, and second, how to
avoid it?
Best
regards,
AnL.
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