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Re: invisible var content to echo when not quoted - why
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From: |
Lawrence Velázquez |
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Subject: |
Re: invisible var content to echo when not quoted - why |
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Date: |
Sun, 28 Nov 2021 12:12:40 -0500 |
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User-agent: |
Cyrus-JMAP/3.5.0-alpha0-1371-g2296cc3491-fm-20211109.003-g2296cc34 |
On Sun, Nov 28, 2021, at 3:52 AM, Alex fxmbsw7 Ratchev wrote:
> declare 's=1 foo["$s"]=asd' ; declare -p s foo ; echo $s ; echo "$s" ; echo
> fin
>
> declare -- s="1 foo[\"\$s\"]=asd"
> bash: declare: foo: not found
>
> 1 foo["$s"]=asd
> fin
>
>
> notice the empty line
I don't see one.
$ printf '%s\n' "$BASH_VERSION"
5.1.8(1)-release
$ unset s foo
$ declare 's=1 foo["$s"]=asd' ; declare -p s foo ; echo $s ; echo "$s" ;
echo fin
declare -- s="1 foo[\"\$s\"]=asd"
bash: declare: foo: not found
1 foo["$s"]=asd
1 foo["$s"]=asd
fin
--
vq