Re: case statement with non-consecutive numbers

[pauline-galea]

Have also thought about the possibilities provided by

for fi in 0 1 2 3 5 8 13 21; do

Can ranges be handled with such construct?

> Sent: Friday, April 16, 2021 at 9:22 AM
> From: "Dennis Williamson" <dennistwilliamson@gmail.com>
> To: pauline-galea@gmx.com
> Cc: "help-bash" <help-bash@gnu.org>
> Subject: Re: case statement with non-consecutive numbers
>
> On Thu, Apr 15, 2021, 4:17 PM <pauline-galea@gmx.com> wrote:
>
> >
> > What other options could be available besides
> >
> > for ((i=1; i <= 1000; i++)); do
> >
> > Perhaps using $(seq 1 2 20)
> >
> > Anything else?
> >
> > > Sent: Friday, April 16, 2021 at 9:10 AM
> > > From: "Dennis Williamson" <dennistwilliamson@gmail.com>
> > > To: "help-bash" <help-bash@gnu.org>
> > > Subject: Re: case statement with non-consecutive numbers
> > >
> > > On Thu, Apr 15, 2021, 4:04 PM Greg Wooledge <greg@wooledge.org> wrote:
> > >
> > > > On Thu, Apr 15, 2021 at 03:57:42PM -0500, Dennis Williamson wrote:
> > > > > On Thu, Apr 15, 2021, 3:30 PM Greg Wooledge <greg@wooledge.org>
> > wrote:
> > > > >
> > > > > for ((i=1; i <= 1000; i++)); do
> > > > >
> > > > >
> > > > > >
> > > > > You can also use complex range specifications in the conditional.
> > > > >
> > > > > for ((i=1; i <= 1000 || (i > 2000 && i <= 3000); i++)); do
> > > >
> > > > That'll abort the loop after 1000, unless something inside the loop
> > > > modifies i to jump it to 2001.
> > > >
> > >
> > >
> > >
> > > Oops you're right.
> > >
> > > >
> > >
> >
>
> Sequential c-style for loops. But that reduces maintainability due to
> repetition of code.
>
> There's no reason to use seq unless you're writing for portability.
>