Re: wait until the file is done

[Chris Elvidge]

On 01/11/2020 11:37 am, MN wrote:
> Thank you Chris!
> I modifed the function as per your suggestion.
> I tried it and it worked well.
>
> How I should increase its verbosity?
>
> [ -e "$1" ] || echo 'No such file'; return 1
>
> Is this any good?
>
> On 20-10-31 18:15:16, Chris Elvidge wrote:
> > On 31/10/2020 04:13 pm, MN wrote:
> > > I thought I would make the function typo-proof.
> > > Is this how it should be done?
> > >
> > > waitfor() {
> > > oldsize=0
> > > if [[ -e "$1" ]]; then         #new lines
> > >       while sleep 30; do
> > >       size=$(wc -c < "$1")
> > >       if ((size > oldsize)); then
> > >           oldsize=$size
> > >           SECONDS=0
> > >           continue
> > >       fi
> > >       if ((SECONDS > 600)); then
> > >           break
> > >       fi
> > >       done
> > > else                           #new lines
> > >       echo 'No such file'        #new lines
> > > fi
> > > }
> >
> > waitfor() {
> >         # return error if $1 not exists
> >         [ -e "$1" ] || return 1
> >         oldsize=0
> >         size=$(wc -c <"$1")
> >         # check if size increased in last 30 seconds
> >         while ((size>oldsize)); do
> >                 oldsize=$size
> >                 sleep 30
> >                 size=$(wc -c <"$1")
> >         done
> > }
> >
> >
> > --
> > Chris Elvidge
> > England

That would need {...} around the echo and return. Pehaps better would be 
[ -s "$1" ] || { echo "No file found/File not found"; return 1; }
-s : checks for file existing and containing something
{ ...; ...; } semicolons are needed inside curly braces
For even more verbosity try a line like
echo -n "$size " or printf "%d " "$size" just before the oldsize=$size 
line (note the space inside the quotes).


--
Chris Elvidge
England