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How to remove output from inherited package?
From: |
Bodertz |
Subject: |
How to remove output from inherited package? |
Date: |
Wed, 25 Dec 2024 20:10:10 -0700 |
User-agent: |
Gnus/5.13 (Gnus v5.13) |
In trying to create a transmission-qt package, I inherit from
transmission, remove the gtkmm dependency and the phases that deal with
moving transmission-gtk to the :gui output, and add a few qt
dependencies so that transmission-qt is built. See the package
definition below:
(define-module (bodertz transmission-qt)
#:use-module (gnu packages bittorrent)
#:use-module (gnu packages qt)
#:use-module (guix packages)
#:use-module (guix gexp)
#:use-module (guix utils))
(define-public transmission-qt
(package
(inherit transmission)
;; (outputs '("out"))
(name "transmission-qt")
(arguments
(substitute-keyword-arguments (package-arguments transmission)
((#:phases phases)
#~(modify-phases #$phases
(delete 'move-gui)
(delete 'glib-or-gtk-wrap)
(delete 'wrap-program)))))
(inputs (modify-inputs (package-inputs transmission)
(delete "gtkmm")
(append qtbase qttools qtsvg)))))
This works fine, except that an unnecessary transmission-qt:gui output
is created which contains license files (apologies if the email messes
up the formatting):
$ tree /gnu/store/k34zx89kvd712maqfi62spnbb5s31bqd-transmission-qt-4.0.6-gui
/gnu/store/k34zx89kvd712maqfi62spnbb5s31bqd-transmission-qt-4.0.6-gui
└── share
└── doc
└── transmission-qt-4.0.6
├── bsd-3-clause.txt
├── COPYING
├── gpl-2.0.txt
├── gpl-3.0.txt
└── mit.txt
When I uncomment the ;; outputs '("out")) line from my package
definition, I expected that it would only create the ordinary :out
output, but instead, I get this error:
$ guix build transmission-qt
[...]
builder for
`/gnu/store/026fwjchyis1x99iqsgliqga284wydbc-transmission-qt-4.0.6.drv' failed
to produce output path
`/gnu/store/v331nyi7kqg4gi432gvhz1c719n8x7xf-transmission-qt-4.0.6-gui'
Is there a way to avoid the attempt to create a :gui output?
- How to remove output from inherited package?,
Bodertz <=