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Re: Syntax-Case macro that selects the N-th element from a list


From: Linus Björnstam
Subject: Re: Syntax-Case macro that selects the N-th element from a list
Date: Mon, 05 Apr 2021 14:21:42 +0200
User-agent: Cyrus-JMAP/3.5.0-alpha0-273-g8500d2492d-fm-20210323.002-g8500d249

Can you use the procedural part of syntax-rules? You have the power of using 
scheme at expansion time, which means you could do list-ref all you want.

The only thing is that guile lacks syntax->list, so sometimes you have to 
manually turn it into a list. Say you are matching ((_ stuff ...) Body) stuff 
is a syntax object. You could turn it into a list of syntax objects by doing  
#'(stuff ...). Then you can treat it as a regular list, and use quasisyntax to 
put it back into your output syntax. 

Writing this on my phone. Sorry for the brevity (and lack of code).

-- 
  Linus Björnstam

On Mon, 5 Apr 2021, at 13:30, Dr. Arne Babenhauserheide wrote:
> Hi,
> 
> In dryads-wake I need selection of the element in a list in a macro from
> user-input. Currently I have multiple macros, and the correct one (which
> strips the non-selected choices) is selected in a simple cond:
> 
> (define-syntax-rule (Choose resp . choices)
>    "Ask questions, apply consequences"
>    (cond
>     ((equal? resp 1) ;; resp is user-input. It is a natural number.
>      (Respond1 choices))
>     ((equal? resp 2)
>      (Respond2 choices))
>     ((equal? resp 3)
>      (Respond3 choices))
>     (else
>      #f)))
> 
> For this however I have three syntax-case macros:
> 
> (define-syntax Respond1
>   (lambda (x)
>     (syntax-case x ()
>       ((_ ((question consequences ...) choices ...))
>         #`(begin
>            (respond consequences ...)))
>       ((_ (choices ...))
>         #`(begin #f)))))
> 
> (define-syntax Respond2
>   (lambda (x)
>     (syntax-case x ()
>       ((_ (choice choices ...))
>         #`(begin
>            (Respond1 (choices ...))))
>       ((_ (choices ...))
>         #`(begin #f)))))
> 
> (define-syntax Respond3
>   (lambda (x)
>     (syntax-case x ()
>       ((_ (a b choices ...))
>         #`(Respond1 (choices ...)))
>       ((_ (choices ...))
>         #`(begin #f)))))
> 
> 
> I would like to get rid of those three definitions and replace them by
> at most two (one that strips N initial list entries, and Respond1).
> 
> I cannot move to procedures, because I have code that must be executed
> only during final processing, and when I evaluate any of the
> consequences (as it happens with procedure-arguments), then the timing
> of the code execution does not match anymore. So I must absolutely do
> this in macros.
> 
> 
> I’ve tried to get that working, but all my tries failed. Is there a way
> and can you show it to me?
> 
> This is a minimal working example. The output should stay the same,
> except for part 4, which needs this change to work (see at the bottom),
> but I would like to:
> 
> - replace Respond2 and Respond3 by something recursive, so resp can have
>   arbitrary high values (not infinite: max the length of the options) and
> - replace the cond-clause by a call to the recursive macro.
> 
> (define-syntax-rule (respond consequence consequence2 ...)
>   (begin
>     (write consequence)
>     (when (not (null? '(consequence2 ...)))
>       (write (car (cdr (car `(consequence2 ...))))))))
> 
> (define-syntax Respond1
>   (lambda (x)
>     (syntax-case x ()
>       ((_ ((question consequences ...) choices ...))
>         #`(begin
>            (respond consequences ...)))
>       ((_ (choices ...))
>         #`(begin #f)))))
> 
> (define-syntax Respond2
>   (lambda (x)
>     (syntax-case x ()
>       ((_ (choice choices ...))
>         #`(begin
>            (Respond1 (choices ...))))
>       ((_ (choices ...))
>         #`(begin #f)))))
> 
> (define-syntax Respond3
>   (lambda (x)
>     (syntax-case x ()
>       ((_ (a b choices ...))
>         #`(Respond1 (choices ...)))
>       ((_ (choices ...))
>         #`(begin #f)))))
> 
> 
> (define-syntax-rule (Choose resp . choices)
>    "Ask questions, apply consequences"
>    (cond
>     ((equal? resp 1)
>      (Respond1 choices))
>     ((equal? resp 2)
>      (Respond2 choices))
>     ((equal? resp 3)
>      (Respond3 choices))
>     (else
>      #f)))
> 
> 
> (display "Choose 1: should be bar:")
> (Choose 1 (foo 'bar) (foo 'war 'har) (foo 'mar) (foo 'tar))
> (newline)
> (display "Choose 2: should be warhar:")
> (Choose 2 (foo 'bar) (foo 'war 'har) (foo 'mar) (foo 'tar))
> (newline)
> (display "Choose 3: should be mar:")
> (Choose 3 (foo 'bar) (foo 'war 'har) (foo 'mar) (foo 'tar))
> (newline)
> (display "Choose 4: should be tar:")
> (Choose 4 (foo 'bar) (foo 'war 'har) (foo 'mar) (foo 'tar))
> (newline)
> (display "Choose 5: should be #f:")
> (Choose 5 (foo 'bar) (foo 'war 'har) (foo 'mar) (foo 'tar))
> (newline)
> 
> 
> Best wishes,
> Arne
> -- 
> Unpolitisch sein
> heißt politisch sein
> ohne es zu merken
> 
> Attachments:
> * signature.asc



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