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Re: Surprising behavior of eq?


From: Zelphir Kaltstahl
Subject: Re: Surprising behavior of eq?
Date: Sun, 20 Sep 2020 15:09:30 +0200
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:68.0) Gecko/20100101 Icedove/68.10.0

And I've noticed something more about equality stuff in the context of
tests:

~~~~
(eqv? "a" "a")
$3 = #t

;; but

(define char->string
  (λ (c)
    (list->string
     (list c))))

(import
  ;; unit tests
  (srfi srfi-64))

(test-begin "string-utils-test")

(test-group
 "char-to-string-test"

 (test-eqv "char->string converts a character to a string"
   "a"
   (char->string #\a)))

(test-end "string-utils-test")

%%%% Starting test string-utils-test  (Writing full log to 
"string-utils-test.log")
$2 = ("string-utils-test")
:19: FAIL char->string converts a character to a string
# of unexpected failures  1
~~~~

So while (eqv? ...) gives the correct (?) result, the test procedure
(test-eqv ...) which seems to indicate using (eqv? ...) via its name
does not think of the two strings as equivalent.


On 20.09.20 14:19, Zelphir Kaltstahl wrote:
> Sorry, I misclicked "send" when I wanted to further edit my e-mail ...
>
> My Guile version is:
>
> ~~~~
> (version)
> $6 = "3.0.4"
> ~~~~
>
> On 20.09.20 14:16, Zelphir Kaltstahl wrote:
>> Hello Guile users,
>>
>> I just noticed something weird about eq?.
>>
>> My Guile version is:
>>
>>
>> I get the different results, depending on whether I define some
>> bindings in a let or using define:
>>
>> (In Emacs Geiser:)
>>
>> ~~~~
>> (define x '(10 9))
>> (define y '(10 9))
>> (eq? x y)
>> $2 = #f
>>
>> (let ([x '(10 9)]
>>       [y '(10 9)])
>>      (eq? x y))
>> $3 = #t
>> ~~~~
>>
>> Is this intentional or a bug?
>>
>> I first noticed something strange when writing the following code:
>>
>> ~~~~DEFINITION~~~~
>> (define make-multiple-list-remover
>>   (λ (equal-proc)
>>     (λ (lst unwanted)
>>       (let loop ([remaining-list lst])
>>         (cond
>>          [(null? remaining-list)
>>           '()]
>>          [(equal-proc (car remaining-list) unwanted)
>>           (loop (cdr remaining-list))]
>>          [else
>>           (cons (car remaining-list)
>>                 (loop (cdr remaining-list)))])))))
>> ~~~~
>>
>> ~~~~TEST~~~~
>> (let ([a '(9 10)]
>>       [b '(9 10)])
>>   (test-equal "make-multiple-list-remover-03"
>>     `(1 2 (3) (4) ,a)
>>     ((make-multiple-list-remover eq?)
>>      `(a b (c) (d) ,a) b)))
>> ~~~~
>>
>> I was wondering, why the test fails. I think (eq? ...) should not be
>> able to see the equivalence of both lists a and b, just like when
>> defined using (define ...).
>>
>> I can also run it in the REPL and see the difference:
>>
>> ~~~~
>> (define a '(9 10))
>> (define b '(9 10))
>> ((make-multiple-list-remover eq?)
>>  `(a b (c) (d) ,a) b)
>> $4 = (a b (c) (d) (9 10))
>>
>> (let ([a '(9 10)]
>>       [b '(9 10)])
>>   ((make-multiple-list-remover eq?)
>>    `(a b (c) (d) ,a) b))
>> $5 = (a b (c) (d))
>> ~~~~
>>
>> Somehow the bindings of let seem to be different from the bindings
>> created using define. What about using define inside let?
>>
>> ~~~~
>>
>> ~~~~
>> -- 
>> repositories: https://notabug.org/ZelphirKaltstahl
> Somehow the bindings of let seem to be different from the bindings
> created using define. What about using define inside let?
>
> ~~~~
> (let ([unrelated 'bla])
>   (define a '(9 10))
>   (define b '(9 10))
>   ((make-multiple-list-remover eq?)
>    `(a b (c) (d) ,a) b))
> $7 = (a b (c) (d))
> ~~~~
>
> So there the define usage also differs from when I use define on the top
> level. Perhaps that is the difference? On which level the bindings are
> defined?
>
> Regards,
> Zelphir
>
-- 
repositories: https://notabug.org/ZelphirKaltstahl



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