Re: [Groff] .lf with single argument?

[Werner LEMBERG]

> Here's AIX 3.2.5.  If it doesn't answer your question, let me know.
> 
>     $ cat j
>     .nf
>     \n(.c '\n(.F'
>     .lf 42 mol
>     \n(.c '\n(.F'
>     .lf 314
>     \n(.c '\n(.F'
>     .lf \n(.c \n(.F
>     \n(.c '\n(.F'
>     \n(.c '\n(.F'
>     $ nroff <j | sed -n /./p
>     1 '<standard input>'
>     41 'mol'
>     312 'mol'
>     312 'mol'
>     313 'mol'
>     $ 

Thanks.  It answers my question.  Note that .lf and \n[.c] work
differently for groff; your example yields

  2 '<standard input>'
  42 'mol'
  314 'mol'
  315 'mol'
  316 'mol'

which is IMHO better.  The original explanation in CSTR 54 doesn't
help to clarify the issue since it is ambiguous:

  The number register `.c' contains the number of input lines read
  from the current file [...]

Personally, I think that groff does the right thing -- to process an
input line it has to be read first, so the `number of input lines read
from the current file' contains the current input line also.
Consequently, .lf sets the line number of the *next* input line.

What do other troff implementations return for Ralph's example?


    Werner