[Geiser-users] issue with using quack with racket and geiser

[Ali Asad Lotia]

Version info:
Geiser: cloned from git repo. Commit ID:
4826d33808c8c54bbe455639c942fc3f789383c0
Racket: v5.0.2
Quack: 0.40

Relevant stuff from emacs init file:
(setq racket-dist-dir "/Applications/Racket v5.0.2/")
(load "geiser-load")
(setq geiser-repl-history-filename (concat local-scratch-dir "geiser-history"))
(setq geiser-racket-binary (concat racket-dist-dir "bin/racket"))
(setq geiser-active-implementations '(racket))
(add-hook 'geiser-repl-mode-hook 'awesome-paredit-hook)
(setq quack-global-menu-p nil)
(require 'quack)

I'm using geiser and racket to work through The Little Schemer (4th
edition) and when I attempt to enter the following in a scheme buffer:
(define lat?
  (lambda (l)
    (cond
     ((null? l) #t)
     ((atom? (car l)) (lat? (cdr l)))
     (else #f))))

I get an error when I type the "#" symbol before "f" in the final
expression of the cond. A buffer titled "*spurious*" comes up with the
following text:
== Contents of *spurious* buffer ==
stdin::6637: else: not allowed as an expression in: else


 === context ===
/Applications/Racket v5.0.2/collects/racket/private/misc.rkt:74:7

racket@> stdin::6642: cond: bad syntax in: cond


 === context ===
/Applications/Racket v5.0.2
== end contents of *spurious* buffer ==

The value of the number after "stdin::" is different, but I get this
error whenever I attempt to enter a second "#" symbol in a scheme
buffer. I don't see the error if I don't have quack loaded.

Please let me know if this has nothing to do with geiser and should be
reported to the author of quack instead.

Thanks,
Ali