Re: [Devel] FTC_Manager_New num_sizes question

[David Turner]

Hello,

Ken Hancock wrote:
> I had been going under the assumption that:
>
> num_faces = 2
> num_sizes = 2
>
> Would mean that in my cache I could have Arial 14 & 18 point as well as
> Times 14 & 18 point.  However, looking at FTC_SCALER_COMPARE it seems that
> it checks the face_id as well as the size which means that I can only have
> only two of the above 4 combinations.

Nope, "num_faces" and "num_sizes" correspond to the maximum number of
concurrent faces and sizes that are held in the cache, and since each
size depends on a face, you'll need "num_faces=2" and "num_sizes=4"
to get what you want.

(don't worry, this will really use 2 sizes per face)

> Is this the original intention?  Is there a clearer way to document this?  A
> default of 4 sizes in light of this seems a bit small...

The default are conservative and appropriate for embedded systems, use
different values if you want.

Regards,

- David Turner
- The FreeType Project  (www.freetype.org)


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