Dear JeanNoël,
Now it is clear for me. Thank you very much for your effort. I really appreciate that.
Best Regards,
AhmadReza
Sent from my iPhone
Hi,
The way I understand it, we define an arbitrary quantity of energy [E] to serve as a scale, to which we assign the value of the statistical thermal energy of the system, [E] = 300 kbT, which has the unit of Joules. We instantiate the electrokinetics class
with a force density of 0.1 on the capacitor plates, so the value of the electric field E generated between the plates can be expressed as E = 0.1[E]/([q][x]) in simulation units (because V/m = J/C/m), which is equal to 0.1 * 4.14e21 / 1.60e19 / 1e9 = 2.5875e6
J/C/m in SI units.
The notation got me confused at first, because the electric field E has units of Volts/meter while the energy [E] has units of Joules.
Best regards,
JN
On 12/11/19 6:46 PM, Ahmad Reza Motezakker wrote:
Dear EspressoMD users,
I am going through Tutorial 7: Electrokinetics and as you know it begins with SI unit conversion to Espresso units. There is a table which shows the necessary parameters for the simulation and their units. I have been able to
convert all the parameters but the last one which is external electric fields (E).
In other words, I am confused that how 2.585*10^6 (V/m) has been transferred to 0.1 [E]/[q][x].
I really appreciate if you could help me with this. Thank you very much.
Best Regards,
Ahmad Reza
