Re: How to use non-font-lock face in font-lock-keywords?

[Lennart Borgman]

On Wed, Dec 23, 2009 at 10:59 PM, Drew Adams <address@hidden> wrote:
>> >> 1. `font-lock-function-name-face' is a variable (whose
>> >>    value is the symbol `font-lock-function-name-face').
>> >>    There is no variable `bold'.
>> >>
>> >> 2. When you use
>> >>    (list (list (concat "\\(?:[`]?" regex "['(]\\)") 1 'bold))))
>> >>
>> >>    you get a list with the face name (symbol), but it is not quoted.
>> >
>> > You are right, I have to use (quote 'bold), and then it works.
>>
>>
>> I think Drew said (quote bold).
>
> Nope. Tassilo understood correctly. In the source code, you need (quote (quote
> bold)), which evaluates to (quote bold). The point is that the face name needs
> to be quoted in the result.
>
> I suggested
>
> `((,(concat "\\(?:[`]?" regex "['(]\\)") 1 'bold))
>
> which is equivalent to using (quote (quote bold)) and which produces (quote
> bold).


I see. Wrong context.