Re: Question about byte-compiler warning

[Richard Stallman]

The compiler is not smart enough to deduce that this code

    (cond
     ((featurep 'xemacs)
      (defun bar ()
        (message "bar XEmacs"))
      (defun foo ()
        (bar)))
     (t
      (defun bar ()
        (message "bar Emacs"))
      (defun foo ()
        (bar))))

always defines bar.  And it is not smart enough to recognize that each
use of bar is in the same conditionals as some definition of bar.