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From: | George Edwards |
Subject: | Re: Problem with OOT Interpolator Python module |
Date: | Sat, 23 Jan 2021 19:00:07 -0600 |
Hi George - I'm presuming the enclosed example.py script is what you're trying calculate - and that the input data is complex.
I invented my own data.
If true, it should be easy to adapt it to your problem by combining the 2 loops for any value of n.
-- Cinaed
On 1/22/21 10:49 AM, George Edwards wrote:
Hello,
I am working with the OOT Interpolator template and I set the interpolation factor to 2. In the QA file I input 5-complex samples and based on my simple code below in the work() method, I expect the QA test to return 1+j1, 10-times (5x2). The QA returns ((1+1j), (1+1j), 0j, 0j, 0j, 0j, 0j, 0j, (1+1j) , (1+1j)). I have tried a lot of different coding permutations and this is the closest I come to a solution, but it is wrong!!! Any help is greatly appreciated!def work(self, input_items, output_items):
in0 = input_items[0]
out = output_items[0]
for ii in range(0,len(in0)):
for k in range(0,2):
out[k] = 1.0+1.0*1j
return len(output_items[0])
Thanks,George
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