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Re: [Chicken-hackers] (load ...)
From: |
Alejandro Forero Cuervo |
Subject: |
Re: [Chicken-hackers] (load ...) |
Date: |
Thu, 7 Jun 2007 16:54:34 +0000 |
User-agent: |
Mutt/1.5.13 (2006-08-11) |
> So, in the case of compiling two files, one having (declare (uses x))
> and the other (declare (unit x)) and compiling with two separate
> commands (as in the manual), how does Chicken share the knoweldge about
> what functions to call in unit x?
>
> like:
>
> csc -c foo.scm
> csc -c bar.scm
> csc bar.o scm.o -o a.out
>
> How does the user of x know the name of the function in unix to invoke to
> the linker gets it right?
I must admit I fail to understand your question.
I also fail to see any relation between this and your previous
question. In this example you are not using load at all, AFAICT. In
this case both files get compiled and linked in a.out.
Thanks.
Alejo.
http://azul.freaks-unidos.net/
- [Chicken-hackers] (load ...), Peter Keller, 2007/06/07
- Re: [Chicken-hackers] (load ...), Alejandro Forero Cuervo, 2007/06/07
- Re: [Chicken-hackers] (load ...), Peter Keller, 2007/06/07
- Re: [Chicken-hackers] (load ...),
Alejandro Forero Cuervo <=
- Re: [Chicken-hackers] (load ...), Peter Keller, 2007/06/07
- Re: [Chicken-hackers] (load ...), Graham Fawcett, 2007/06/07
- Re: [Chicken-hackers] (load ...), Graham Fawcett, 2007/06/07
- Re: [Chicken-hackers] (load ...), Peter Keller, 2007/06/07
- Re: [Chicken-hackers] (load ...), Graham Fawcett, 2007/06/07
- Re: [Chicken-hackers] (load ...), Peter Keller, 2007/06/08
- Re: [Chicken-hackers] (load ...), John Cowan, 2007/06/08
- Re: [Chicken-hackers] (load ...), John Cowan, 2007/06/07
Re: [Chicken-hackers] (load ...), Alejandro Forero Cuervo, 2007/06/07