[bug #33080] combination of --count (-c) and --only-matching (-o)

[Seungbeom Kim]

URL:
  <http://savannah.gnu.org/bugs/?33080>

                 Summary: combination of --count (-c) and --only-matching (-o)
                 Project: grep
            Submitted by: musiphil
            Submitted on: Thu 14 Apr 2011 04:32:25 PM PDT
                Category: None
                Severity: 3 - Normal
              Item Group: None
                  Status: None
                 Privacy: Public
             Assigned to: None
             Open/Closed: Open
         Discussion Lock: Any

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Details:

--only-matching (-o) causes grep to print all the matching parts separately,
no matter how many times such parts occur on a single line. For example:

$ cat > test.txt
true true false
false true
false
true false true
$ grep --only-matching b test.txt
true
true
true
true
true

If you want to count how many matches you have, you naturally think you can
use --count (-c). But you can't:

$ grep --only-matching --count true test.txt
3

You still get the number of "lines" that match the pattern, not how many
"matches". The --only-matching option is effectively ignored, in a silent
way.

This is counter-intuitive, when you consider that 'grep --count ...' is
generally equivalent to 'grep ... | wc -l', which doesn't hold if
--only-matching is used.

$ grep true test.txt | wc -l
3
$ grep --count true test.txt
3
$ grep --only-matching true test.txt | wc -l
5
$ grep --only-matching --count true test.txt
3

I suggest that grep --count should print the number of lines that would be
printed without --count, whether or not --only-matching is used; that is, the
number of lines that match the pattern without --only-matching, and the number
of matches with --only-matching.




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