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Re: [gnubg] Help with a new MET

From: Timothy Y. Chow
Subject: Re: [gnubg] Help with a new MET
Date: Tue, 12 Nov 2019 17:52:51 -0500 (EST)
User-agent: Alpine 2.21 (LRH 202 2017-01-01)

On Wed, 13 Nov 2019, Joseph Heled wrote:
I thought it was clear that what we want to establish a difference between two (say players X and Y) by running games and testing that gammon-rate(X) != gammon-rate(Y).

Thanks for the clarification.

If you're pitting X against Y and your null hypothesis is that their playing abilities are identical, then what I'd recommend is something like this. Collect two sets of samples. In the first sample, play a bunch of games and form a vector of counts like this:

(X wins BG, X wins G, X wins S, Y wins S, Y wins G, Y wins BG)

In the second sample, play the same number of games, and form a similar vector but reverse the order of the counts:

(Y wins BG, Y wins G, Y wins S, X wins S, X wins G, X wins BG)

Now you've reduced your problem to testing whether these two sets of sample vectors come from the same distribution. There are various ways one can do this, a standard one being a chi squared two-sample test.



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