Re: sub("@\^","^",$0) doesn't

[cw02]

Thanks! I confirmed that
sub("@\\^","^",$0)
works on HP-UX, Solaris and Linux.

> From address@hidden  Sun Dec 22 00:52:59 2002
> Date: Fri, 20 Dec 2002 10:42:30 +0200
> From: Aharon Robbins <address@hidden>
> Message-Id: <address@hidden>
> To: address@hidden, address@hidden
> Subject: Re: sub("@\^","^",$0) doesn't

> Greetings. Re this:
> 
> > From: "Clinton Wittstruck" <address@hidden>
> > To: <address@hidden>
> > Subject: sub("@\^","^",$0) doesn't
> > Date: Thu, 19 Dec 2002 17:25:51 -0800
> > Content-Transfer-Encoding: quoted-printable
> >
> > I've noticed a weird discrepency between awk on HP-UX 11.0 and Red Hat
> > Linux 2.2.16-22 (GNU Awk 3.0.6 -- I also downloaded and tested gawk
> > 3.1.1)
> >
> > For an occurance of "@^", substitue "^" -- (strip out the "@" before
> > "^")
> >
> > I tried: sub("@\^","^",$0)
> >
> > On HP-UX awk this works but with gawk on Linux it does not.
> 
> You need an extra backslash in the string. For string constants,
> you always need two backslashes to get sub/gsub to see one. This
> is described in the gawk manual.  Here is what I get:
> 
>       $ echo here is an @^ | gawk '{ sub("@\\^", "^", $0); print }'
>       here is an ^
> 
> Thanks,
> 
> Arnold
>