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Re: How to get the default value of --max-args?
From: |
Bernhard Voelker |
Subject: |
Re: How to get the default value of --max-args? |
Date: |
Thu, 8 Nov 2018 11:50:29 +0100 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:60.0) Gecko/20100101 Thunderbird/60.2.1 |
On 11/8/18 6:50 AM, Peng Yu wrote:
> Hi,
>
> It seems that the default value for --max-args is system dependent. Is
> there a way to find out its default value? Thanks.
Actually the limit is not a matter of the number of arguments but that
of the resulting total command line length.
>From 'man xargs':
--show-limits
Display the limits on the command-line length which are imposed by the
operating system, xargs' choice of buffer size and the -s option.
Pipe the input from /dev/null (and perhaps specify --no-run-if-empty)
if you don't want xargs to do anything.
So here it is:
$ xargs --show-limits </dev/null
Your environment variables take up 3163 bytes
POSIX upper limit on argument length (this system): 2091941
POSIX smallest allowable upper limit on argument length (all systems): 4096
Maximum length of command we could actually use: 2088778
Size of command buffer we are actually using: 131072
Maximum parallelism (--max-procs must be no greater): 2147483647
It's "actually using: 131072".
So even if you specify a higher number like 'xargs -n 200000', and all the
arguments only have 1 character, then still the number of actual arguments
for each program execution cannot be larger than about 131072/2 minus a few
bytes:
echo called only once:
$ yes . | head -n $(bc <<<'131072 /2 - 3') | xargs -tn 200000 2>&1 | tr -d
'[. ]'
echo
echo called twice:
$ yes . | head -n $(bc <<<'131072 /2 - 2') | xargs -tn 200000 2>&1 | tr -d
'[. ]'
echo
echo
Have a nice day,
Berny