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[bug #40648] xargs -t does not show EXACT command line
From: |
anonymous |
Subject: |
[bug #40648] xargs -t does not show EXACT command line |
Date: |
Wed, 20 Nov 2013 17:06:29 +0000 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/31.0.1650.57 Safari/537.36 |
URL:
<http://savannah.gnu.org/bugs/?40648>
Summary: xargs -t does not show EXACT command line
Project: findutils
Submitted by: None
Submitted on: Wed 20 Nov 2013 05:06:28 PM UTC
Category: xargs
Severity: 3 - Normal
Item Group: Wrong result
Status: None
Privacy: Public
Assigned to: None
Originator Name: Anne van Rossum
Originator Email: address@hidden
Open/Closed: Open
Discussion Lock: Any
Release: None
Fixed Release: None
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Details:
Bug:
To reproduce:
$ mkdir "example 1"
$ mkdir "example 2"
Here "nautilus" is just an example program that does choke on something
provided by spaces:
$ ls --quoting-style=literal | grep example | xargs -t nautilus
nautilus example 1 example 2 examples
$ ls --quoting-style=shell | grep example | xargs -t nautilus
nautilus example 1 example 2 examples
The former option does fail to open with nautilus ("example", "1", and "2" are
opened), while the second properly does open nautilus properly.
Expected:
What I would expect as xargs -t output is the following:
$ ls --quoting-style=literal | grep example | xargs -t nautilus
nautilus example 1 example 2 examples
$ ls --quoting-style=shell | grep example | xargs -t nautilus
nautilus 'example 1' 'example 2' examples
So, I would expect it to have the quotes from the ls --quoting-style=shell |
grep example command
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