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bug#20928: cut (v. 8.21), using -f option with a single column
From: |
Kuchta, Tomasz |
Subject: |
bug#20928: cut (v. 8.21), using -f option with a single column |
Date: |
Mon, 29 Jun 2015 15:37:29 +0000 |
Hi Pádraig,
Oh, I see - thanks for letting me know.
Kind regards,
Tomek
> On 29 Jun 2015, at 16:31, Pádraig Brady <address@hidden> wrote:
>
> tag 20928 notabug
> close 20928
> stop
>
> On 29/06/15 09:18, Kuchta, Tomasz wrote:
>> Hello.
>>
>> I’m not sure if this is a bug - I just wanted to let you know.
>> Thanks,
>> Tomek
>>
>> ——
>>
>> When there is more than one column and we go beyond the number of columns
>> with the -f option, the output is empty
>>
>> $ echo "test1 test2" | cut -d' ' -f1
>> test1
>> $ echo "test1 test2" | cut -d' ' -f2
>> test2
>> $ echo "test1 test2" | cut -d' ' -f3
>>
>> $
>>
>> ——
>>
>> When there is only one column and we go beyond 1 with the -f option, the
>> output remains the first column
>>
>> $ echo "test1" | cut -d' ' -f1
>> test1
>> $ echo "test1" | cut -d' ' -f2
>> test1
>> $ echo "test1" | cut -d' ' -f3
>> test1
>
> That difference in behavior is there for compat reasons.
> To induce the behavior you expect, you need the -s option.
>
> thanks,
> Pádraig.
>