Re: Did I found a bug in "ls"?

[Major Péter]

Hi,

I need to write a script, which will print out on the standard output, 
that each user how many disk space (in blocks) are using in a directory 
(and subdirectories, the directory is a parameter).
So an example output would look like this:
root:101711
user1:940258

The main problem with du is, that it doesn't care with users, so I need 
a "find" before (using the -user will solve the problem). But I can't 
use du `find ...` because it will contain the subfolders too, so it will 
duplicate, and the measure won't be correct. (Or if I'm use the 
--max-depth option it will still not care with the user filtering).
So by now I have this:
du `find . -type f -user foobar`
using sed, and a for cycle I can make a sum from this values.
But now, I don't have the sizes of the directories, so that's why I 
tried to use:
ls `find . -type d -user foo -name "*"` # -name "*" will be removed in 
the final version
but didn't worked, so I wrote here a mail.
If you know a better way, please just send me a command or parameter 
name, because this is my homework. :)
I will use the -print0 parameter with xargs.
Thanks for helping me.

Regards,
Peter

Philip Rowlands írta:
> On Sun, 8 Mar 2009, Major Péter wrote:
>
> > I would like to list some folders with they block-sizes, but only 
> > specific folders am I interested.
> > So I would like to use find to list the correct folders for me:
> > ls `find . -type d -user foo -name "*"`
> > this is not working because ls can't find folders with spaces in 
> > there name,
>
> find uses an implicit "-print" argument, but in this case please look 
> at find's "-print0" option. This version of the above command should 
> work:
>
> $ find . -type d -user foo -print0 | xargs -0 ls
> (-name "*" is redundant, as everything matches)
>
> I'm still not sure what you're referring to by folders with 
> block-sizes? Would the du command be helpful here?
>
>
> Cheers,
> Phil