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[Bug gas/1038] resolution of weak symbol not left for the linker if valu


From: bryanmcsp at gmail dot com
Subject: [Bug gas/1038] resolution of weak symbol not left for the linker if value is already known
Date: Wed, 10 Nov 2021 14:13:16 +0000

https://sourceware.org/bugzilla/show_bug.cgi?id=1038

Takkelink <bryanmcsp at gmail dot com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |bryanmcsp at gmail dot com

--- Comment #6 from Takkelink <bryanmcsp at gmail dot com> ---
https://www.southdublinroofers.ie
avr-libc's C run-time startup code uses something like the following to
initialize the stack:

        .weak   __stack
        .set    __stack, RAMEND
...
        ldi     r28,lo8(__stack)
#ifdef SPH
        ldi     r29,hi8(__stack)
        out     _SFR_IO_ADDR(SPH), r29
#endif
        out     _SFR_IO_ADDR(SPL), r28

Here, RAMEND as a C preprocessor macro that depends on the actual processor
type this code is being compiled for, and which evaluates to a 16-bit
number by the time this code is being assembled.

The idea behind that is that while the stack initially starts at top of
RAM (growing downwards), the user can tune the actual stack location at
link time by supplying a different value for the weak symbol __stack.

However, as the value of __stack is already known to the assembler at
that point, the assembler actually inserts the fixed value RAMEND instead
of a reference to the weak symbol __stack, thereby entirely defeating the
idea behind marking __stack as `weak' in the first place.

By reordering the code, and placing the definition of __stack behind its
use in the assembly code, the problem can be worked around, but I believe
the assembler must not resolve symbols marked as `weak' in the first place
but always leave that to the linker.

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