declare XXX=$(false);echo $?

[Ulrich Windl]

Surprisingly "declare XXX=$(false);echo $?" outputs "0" (not "1")
There is no indication in the manual page that "declare" ignores the exit code 
of commands being executed to set values.
Actually I's consider it to be a ASH bug, not a documentation bug.

Found in the real code (intended to trigger a bug):
    declare ERRORS=0 ARGS=$(getopt -o "$S_OPTS" -l "$L_OPTS" -n "$0" -- "$@")

    if [ $? -ne 0 ]; then
        usage
    fi

++ getopt -o e:i:v -l exclude:,include:,verbose -n ./buggy.sh -- add -vv 
-iHCTL_DEFS -k SAPDA_DEFS -- -p
./buggy.sh: invalid option -- 'k'
+ declare ERRORS=0 'ARGS= -v -v -i '\''HCTL_DEFS'\'' -- '\''add'\'' 
'\''SAPDA_DEFS'\'' '\''-p'\'''
+ '[' 0 -ne 0 ']'