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Re: No word splitting for assignment-like expressions in compound assign
From: |
Ilkka Virta |
Subject: |
Re: No word splitting for assignment-like expressions in compound assignment |
Date: |
Tue, 28 Jul 2020 23:14:48 +0300 |
User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.13; rv:68.0) Gecko/20100101 Thunderbird/68.10.0 |
On 28.7. 17:22, Chet Ramey wrote:
On 7/23/20 8:11 PM, Alexey Izbyshev wrote:
$ Z='a b'
$ A=(X=$Z)
$ declare -p A
declare -a A=([0]="X=a b")
It's an assignment statement in a context where assignment statements are
accepted (which is what makes it different from `echo X=$Z', for instance),
but the lack of a subscript on the lhs makes it a special case. I'll take a
look at the semantics here.
This is also a bit curious:
$ b=( [123]={a,b,c}x )
$ declare -p b
declare -a b=([0]="[123]=ax" [1]="[123]=bx" [2]="[123]=cx")
It does seem to have a subscript on the LHS, but it didn't work as one.
To be in line with a plain scalar assignment, the braces should probably
not be expanded here.
--
Ilkka Virta / itvirta@iki.fi
Re: No word splitting for assignment-like expressions in compound assignment, Chet Ramey, 2020/07/28
- Re: No word splitting for assignment-like expressions in compound assignment,
Ilkka Virta <=