Re: Return from function depending on number of parameters

[Chris Elvidge]

On 06/07/2020 12:50 pm, Greg Wooledge wrote:
> On Fri, Jul 03, 2020 at 07:00:54PM +0100, Chris Elvidge wrote:
> > I've used 'return $((!$#))' and 'return $[!$#]' to return an error if no
> > parameters given to function.
>
> The problem with this is that it *always* returns from the function,
> even when paramters are given.
>
> If you actually want to do what you said, you need a conditional check
> of some kind, either "if" or "||".
>
> (($#)) || return 1
>
> would be my preference, if you really do not want to give any kind of
> error message to indicate *why* you are returning with a failure code.
>
> If you want to add an error message, then I would go with "if".
>
> if ((! $#)); then
>    echo "usage: myfunc arg1 ..." >&2
>    return 1
> fi

This is a function only for me. The return comes after a help section.
[[ $# -eq 0 || "$1" =~ -h ]] &&  etc. No error message required, just an 
indication.

Thanks for the pointers.

--
Chris Elvidge
England