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From: | Martijn Dekker |
Subject: | Re: [BUG] 'unset' fails silently under specific conditions |
Date: | Tue, 1 May 2018 23:27:26 +0100 |
User-agent: | Mozilla/5.0 (Macintosh; Intel Mac OS X 10.11; rv:52.0) Gecko/20100101 Thunderbird/52.7.0 |
Op 01-05-18 om 19:36 schreef Chet Ramey:
OK, so which is it? Does an assignment statement preceding a special builtin in a shell function create a local variable (as we discussed just yesterday)
Huh? That was about 'typeset'/'declare'. How is that relevant here?
or does it create a global variable because `Posix'?
Yes. POSIX does not specify local variables at all, and even in a bash context I see nothing there to indicate that it should be local.
The possibility that 'foo=bar :' might create a variable 'foo' that survives the ':' command, is exported, *and* is local to the function, hadn't occurred to me at all. POSIX is pretty strange sometimes but not *this* strange.
- M.
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