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Re: completion considers equals sign (=) its own word?
From: |
Chet Ramey |
Subject: |
Re: completion considers equals sign (=) its own word? |
Date: |
Thu, 17 Dec 2009 10:03:23 -0500 |
User-agent: |
Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.5; en-US; rv:1.9.1.5) Gecko/20091204 Thunderbird/3.0 |
On 12/15/09 6:01 AM, bebarino@gmail.com wrote:
> Configuration Information [Automatically generated, do not change]:
> Machine: i486
> OS: linux-gnu
> Compiler: gcc
> Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='i486'
> -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu'
> -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL
> -DHAVE_CONFIG_H -I. -I../bash -I../bash/include -I../bash/lib -g -O2
> -Wall
> uname output: Linux swboyd-laptop 2.6.31-16-generic #53-Ubuntu SMP Tue Dec 8
> 04:01:29 UTC 2009 i686 GNU/Linux
> Machine Type: i486-pc-linux-gnu
>
> Bash Version: 4.0
> Patch Level: 33
> Release Status: release
>
> Description:
> When completing options for git I used to be able to get a list
> of pretty formats by completing the --pretty= option. The option
> ends in an equals sign, so the completion looks for the word
> --pretty= in the COMP_WORDS array. It turns out that --pretty and =
> are considered two separate words in bash4, but considered one word
> in bash3. Is this intended?
Yes. The programmable completion in bash-4.x uses the same set of
characters to split words as the readline word completion code. Doing
otherwise led to too many weird inconsistencies.
If you want to remove `=' from the set of `completion word break'
characters, you can modify the COMP_WORDBREAKS variable.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/