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Re: exercise 2019/02

From: Kacper Gutowski
Subject: Re: exercise 2019/02
Date: Wed, 15 Apr 2020 01:22:19 +0200

On Tue, Apr 14, 2020 at 05:40:26PM +0200, Otto Diesenbacher-Reinmüller wrote:
2 making the grade
Any hint?

I think all those ranges are mostly a distraction, because it's nowhere said you need to handle out-of-range arguments in any graceful way. I would start with ⍵>table[;2] which is a binary vector for scalar ⍵, and then go from that.

My solution would be {table[⎕IO++/⍵∘.>table[;2];3]}.
Few years ago I would try to use ¨ too (I'm still relatively new to APL myself), but it kinda feels like writing C in APL and outer product is really more natural here when you think about it.

Alternatively you could use dyadic ⍳ to find the first 0 in said vector, which then leads to something like {table[(⍵∘.>table[;2])⍳⍤1⊢0;3]}.


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