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## Re: [Axiom-math] About "%%"

**From**: |
William Sit |

**Subject**: |
Re: [Axiom-math] About "%%" |

**Date**: |
Sun, 15 Jan 2006 16:58:05 -0500 |

Daniel wrote:
>* I'm using Axiom in Debian GNU/Linux for corroborate some results of*
>* numerical calculus. In a exercise of inverse Laplace transform, I've to*
>* calculate f(0) if F(s) = (s**2 - 9*s - 32)/(2*s**3 - 3*s + 4).*
>* *
>* At the begining, I thought to use partial fraction decomposition but the*
>* denominator have irrational roots :-( Then I thought to use Axiom for*
>* give me a idea of its resolution. The fact is that inverseLaplace give*
>* me %%A0 or %%AO squared in the solution. How this values are*
>* interpreted?*
The a = %%A0 is the real root of the denominator, which then factors as:
2*s**3 - 3*s + 4 = (s - a)(2*s**2 + 2*a*s + 2*a**2 -3)
The coefficients of t in the exponential functions are the roots of the
quadratic factor based on the quadratic formula. Axiom should have said what
%%A0 is.
William