Re: [Axiom-mail] Generating rules in functions or macros

[Gerald Knizia]

On Tuesday 29 July 2008 07:12, Martin Rubey wrote:
> Gerald Knizia <address@hidden> writes:
> > Is there some way to accomplish something like that? Am I missing
> > something important in they way axiom works? If using functions or macros
> > above does not seem to make any difference.
>
> Maybe you are looking for
>
> eval(expr, [kernel=replacement])
>
> or
>
> eval(expr, operator, arglist +-> transformation(arglist))

Hm.. the eval doesn't seem to be applicable to RewriteRule-objects. I was not 
able to modify a rule using it.

Perhaps, to clarify: I'm not after this particular function F, but trying to 
use parameterized rulesets in a more general context. The F is just the 
simplest rule I could think of.

Maybe I should rephrase my problem. Currently I get this:

(1) -> F(x,y) == (rule 'x == y)
                                                          Type: Void
(2) -> F(A,B)
   Compiling function F with type (Variable A,Variable B) ->
      RewriteRule(Integer,Integer,Expression Integer)

   (2)  x == y
               Type: RewriteRule(Integer,Integer,Expression Integer)

How does the function F need to be defined such that the result of F(A,B)
is equal to the one of
   rule 'A == B
and the result of F(C,D) is equal to
   rule 'C == D
? I am particularly puzzled by the fact in (2) above, not only the function 
argument x is not evaluated, but y also is not (although unquoted).

If I make F a macro instead of a function, in y in F(A,B) is properly 
replaced. But x is not (not even when writing '(x) instead of 'x). Shouldn't 
macros be a simple text replacements and do this?
-- 
Gerald Knizia