[Axiom-mail] New to Axiom: Implement 'Balanced' FiniteField ?

[jim kraai]

Greetings,

(I'm more of a pencil-n-paper math guy.)

A BalancedFiniteField representation of an integer n would be:
  the same as FiniteField (base) if n <= floor(n/2)
  else base - floor(n/2)

Examples:

base of 4     base of 5 
n  FF BFF     n  FF BFF 
----------    ----------
0  0   0      0  0   0  
1  1   1      1  1   1  
2  2   2      2  2   2  
3  3  -1      3  3  -2  
4  0   0      4  0  -1  
5  1   1      5  1   0  
              6  0   0  
                        
After reading the book chapters on Packages, Categorys, and Domains, I find 
that I'm no more clear on which is an effective way to get this output.

Thanks for any help,

--jim



                
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