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RE: [Axiom-developer] RE: learning in public
From: |
Page, Bill |
Subject: |
RE: [Axiom-developer] RE: learning in public |
Date: |
Tue, 1 Jun 2004 21:08:37 -0400 |
Bertfried and Tim,
On Tuesday, June 01, 2004 6:56 PM you wrote:
>
> ... but I still do not see how to do it categorial and in
> a full generality.
> This week I am technically still in vacations and next
> week partly on a conference, so I will have a fast internet
> connection only from pre-next week onwards. I will try to
> take this time to think about a start implementation and what
> it should look like.
>
> Categorical:
>
> From a categorical point of view, there is a functor from the
> spaces having a quadratic (bilinear not necessarily symmetric)
> form into the category of associative algebras. To characterize
> this functor would be the most difficult thing. But this is an
> unsolved math problem.
>
>From http://en.wikipedia.org/wiki/Clifford_algebra
Formal definition
Let V be a vector space over a field k, and q : V -> k a quadratic form on
V. The Clifford Algebra C(q) is a unital associative algebra over k together
with a linear map i : V -> C(q) defined by the following universal property:
for every associative algebra A over k with a linear map j : V -> A such
that for every v in V we have j(v)^2 = q(v)1 (where 1 denotes the
multiplicative identity of A), there is a unique algebra homomorphism
f : C(q) ? A
such that the following diagram commutes:
V ----> C(q)
| /
| / Exists and is unique
| /
v v
A
i.e. such that fi = j.
---------
Definition by a universal property
http://en.wikipedia.org/wiki/Universal_property
is a common method of category theory. Unfortunately it is
rather too abstract on usually non-constructive. Perhaps what
you had in mind is the notion of adjoint functors
http://en.wikipedia.org/wiki/Adjoint_functors
But I think best approach is to start from the general
tensor algebra
http://en.wikipedia.org/wiki/Tensor_algebra
http://planetmath.org/encyclopedia/TensorAlgebra.html
I can imagine that the general construction of the tensor
algebra on a vector space should be quite natural in Axiom -
perhaps most of this is already present in Axiom. But then to
complete the general construction of a Clifford algebra we
need to be able to compute the quotient ring generated by
the quadratic form.
http://planetmath.org/encyclopedia/CliffordAlgebra2.html
I am not so sure how one can do this in Axiom without
introducing a basis. In general we need to be able to
define an equivalence relation over the tensor expressions.
The following paper is rather difficult for me but
seems interesting.
http://www.nd.edu/~alhonors/pages/CliffordFinal.pdf
The Clifford Algebra in the Theory of Algebras, Quadratic
Forms, and Classical Groups by Alexander Hahn.
And the following work by Paul Leopardi also seems very
relevant.
http://cage.rug.ac.be/~krauss/iciam.pdf
http://www.maths.unsw.edu.au/~leopardi/
http://www.maths.unsw.edu.au/~leopardi/clifford-2003-06-05.pdf
http://sourceforge.net/projects/glucat/
Regards,
Bill Page.
- [Axiom-developer] Re: learning in public, root, 2004/06/01
- [Axiom-developer] RE: learning in public, Page, Bill, 2004/06/01
- RE: [Axiom-developer] RE: learning in public,
Page, Bill <=
- RE: [Axiom-developer] RE: learning in public, Page, Bill, 2004/06/08
- Re: [Axiom-developer] RE: learning in public, William Sit, 2004/06/09