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[Qemu-devel] [PATCH] qemu-io: Make alloc output useful when nb_sectors=1
From: |
Stefan Hajnoczi |
Subject: |
[Qemu-devel] [PATCH] qemu-io: Make alloc output useful when nb_sectors=1 |
Date: |
Thu, 2 Sep 2010 10:38:03 +0100 |
There is no indication whether or not the sector is allocated when
nb_sectors=1:
sector allocated at offset 64 KiB
This message is produced whether or not the sector is allocated.
Simply use the same message as the plural case, I don't think the
English is so broken that we need special case output here:
0/1 sectors allocated at offset 64 KiB
This change does not affect qemu-iotests since nb_sectors=1 is not used
there.
Signed-off-by: Stefan Hajnoczi <address@hidden>
---
qemu-io.c | 7 ++-----
1 files changed, 2 insertions(+), 5 deletions(-)
diff --git a/qemu-io.c b/qemu-io.c
index 2dbe20f..bd3bd16 100644
--- a/qemu-io.c
+++ b/qemu-io.c
@@ -1427,11 +1427,8 @@ alloc_f(int argc, char **argv)
cvtstr(offset, s1, sizeof(s1));
- if (nb_sectors == 1)
- printf("sector allocated at offset %s\n", s1);
- else
- printf("%d/%d sectors allocated at offset %s\n",
- sum_alloc, nb_sectors, s1);
+ printf("%d/%d sectors allocated at offset %s\n",
+ sum_alloc, nb_sectors, s1);
return 0;
}
--
1.7.1
- [Qemu-devel] [PATCH] qemu-io: Make alloc output useful when nb_sectors=1,
Stefan Hajnoczi <=