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[Qemu-devel] Re: [PATCH 1/2] qemu-accel: unbreak non-default accelerator


From: Glauber Costa
Subject: [Qemu-devel] Re: [PATCH 1/2] qemu-accel: unbreak non-default accelerators
Date: Tue, 9 Sep 2008 13:49:55 -0300
User-agent: Mutt/1.5.18 (2008-05-17)

On Tue, Sep 09, 2008 at 08:37:37PM +0400, Dmitry Baryshkov wrote:
> Make noaccel accelerator "registered" early so that
> kqemu has a change to be enabled (it's registered
> via __constructor__ feature, so called before main()).
fyi: we're probably changing that. There has been a lot of mail exchange
this days about the general acceptability of this feature, and the overall
feeling is that it's a negative construct. So if the problem you hit happens 
because
the constructor itself, it's probably worthy to drop it altogether, and invest 
time
in a new method for registering the accelerators.

> 
> Signed-off-by: Dmitry Baryshkov <address@hidden>
> Cc: Glauber Costa <address@hidden>
> ---
>  vl.c |    9 +++++----
>  1 files changed, 5 insertions(+), 4 deletions(-)
> 
> diff --git a/vl.c b/vl.c
> index 16c1e15..bf9d83c 100644
> --- a/vl.c
> +++ b/vl.c
> @@ -243,7 +243,6 @@ static CPUState *next_cpu;
>  static int event_pending = 1;
>  
>  QEMUAccel *current_accel;
> -QEMUCont *head = NULL;
>  char qemu_app_name[20] = "QEMU";
>  
>  void decorate_app_name(void)
> @@ -290,6 +289,11 @@ QEMUAccel noaccel = {
>      .break_loop = accel_nop,
>  };
>  
> +QEMUCont *head = &(QEMUCont){
> +     .acc = &noaccel,
> +     .active = 0,
> +};
don't we want to register it as active = 1, for the case we're not using kqemu 
at all?
> +
>  #define TFR(expr) do { if ((expr) != -1) break; } while (errno == EINTR)
>  
>  /***********************************************************/
> @@ -7766,9 +7770,6 @@ int main(int argc, char **argv)
>      }
>  #endif
>  
> -    /* Basic handler for the noaccel case */
> -    register_qemu_accel(&noaccel);
> -
>      register_machines();
>      machine = first_machine;
>      cpu_model = NULL;
> -- 
> 1.5.6.5
> 




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