Re: Release candidate for Qhull 2012.1

[Ben Abbott]

On Jan 29, 2012, at 8:46 PM, Dmitri A. Sergatskov wrote:

> On Sun, Jan 29, 2012 at 7:38 PM, Ben Abbott <address@hidden> wrote:
> 
>> On Matlab ...
>> 
>> cube = [0 0 0;1 0 0;1 1 0;0 1 0;0 0 1;1 0 1;1 1 1;0 1 1];
>> [h, v] = convhulln (cube);
>> 
>> h =
>> 
>>     3     4     2
>>     2     4     1
>>     6     2     1
>>     5     6     1
>>     4     8     1
>>     8     5     1
>>     7     3     2
>>     6     7     2
>>     7     4     3
>>     7     8     4
>>     7     6     5
>>     8     7     5
>> 
>> 
>> v =
>> 
>>     1
>> 
>> [h, v] = convhulln (cube, {'Qt'})
>> 
>> h =
>> 
>>     3     4     2
>>     2     4     1
>>     6     2     1
>>     5     6     1
>>     4     8     1
>>     8     5     1
>>     7     3     2
>>     6     7     2
>>     7     4     3
>>     7     8     4
>>     7     6     5
>>     8     7     5
>> 
>> v =
>> 
>>     1
>> 
>> I get the same with Octave (tip below) on MacOSX 10.7.2 (Lion).
>> 
>> $ hg tip
>> changeset:   14282:b4d7de953066
>> tag:         tip
>> user:        Michael Goffioul <address@hidden>
>> date:        Sun Jan 29 12:53:05 2012 +0000
>> summary:     Export more required symbols [Win32].
>> 
>> Does Fedora really return a 6x4 matrix for the first test?
>> 
>> Ben
> 
> octave:1> cube = [0 0 0;1 0 0;1 1 0;0 1 0;0 0 1;1 0 1;1 1 1;0 1 1];
> octave:2> [h, v] = convhulln (cube);
> octave:3> h
> h =
> 
>   4   1   2   3
>   5   6   2   1
>   8   5   1   4
>   6   7   3   2
>   7   8   4   3
>   8   7   6   5
> 
> Fedora 16 x86_64, octave 3.6.0, qhull 2003.1
> 
> Dmitri.

Using qhull version < 2011 I got the same thing.

Doesn't this result imply that the 6 faces of the cube are being returned and 
not the 12 triangulated faces ?

Given the default option is "Qt" shouldn't the result be triangles?

Ben