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Re: a small fix for hist.m


From: Ben Abbott
Subject: Re: a small fix for hist.m
Date: Wed, 01 Dec 2010 08:24:52 -0500

On Nov 30, 2010, at 10:39 PM, Doug Stewart wrote:

> On Tue, Nov 30, 2010 at 9:33 PM, Doug Stewart <address@hidden> wrote:
>> On Tue, Nov 30, 2010 at 9:19 PM, Ben Abbott <address@hidden> wrote:
>>> On Nov 30, 2010, at 7:35 PM, Doug Stewart wrote:
>>> 
>>>> I am now retired from teaching, and am going to spend some time
>>>> improving the help section of some M files.
>>>> 
>>>> I am learning as I go so please go easy on me :-)
>>>> 
>>>> 
>>>> I have got hg working.
>>>> I have got the tip and made a change to hist.m
>>>> I have attached the diff file.
>>>> 
>>>> I am also suppose to create one more document about the changes.
>>>> Can someone show me how to do this last part
>>>> 
>>>> Doug Stewart
>>>> 
>>>> PS. This is just a small fix for me to learn on.
>>>> <hist.diff>
>>> 
>>> 
>>> I see one minor format mistake. The output and equals sign should be 
>>> enclosed in the curly brackets.
>>> 
>>> Forgive the micro-management, but I assume you'll be adding the various 
>>> modes of operation as well. Perhaps something like ...
>>> 
>>> ## @deftypefn {Function File} {} hist (@var{y})
>>> ## @deftypefnx {Function File} {} hist (@var{y}, @var{x})
>>> ## @deftypefnx {Function File} {} hist (@var{y}, @var{nbins})
>>> ## @deftypefnx {Function File} {} hist (@var{y}, @var{x}, @var{norm})
>>> ## @deftypefnx {Function File} {[nn, xx] =} hist (@dots{})
>>> 
>>> Ben
>>> 
>> 
>> Thank you Ben for the help (mico-managment :-) )
>> Yes   after I get the process figured out I hope to do much more.
>>  And yes I do know about passing the colors through to bar()
>> 
>> I will resubmit this one.
>> Doug
> 
> here is the new diff
> Is there anything else I should do?
> <hist.diff>

The help text can be improved by changes such as ....

-## With one vector input argument, plot a histogram of the values
+## With one vector input argument, @var{y}, plot a histogram of the values

If you're up to a bug fix, it looks to me like the example below does not 
produce the correct result.

y = randn (1, 1000);
x = [0.1, 0.2, 0.5, 0.7 0.9];
hist (y, x)

Matlab gives the attached result. Its not immediately clear to me how the bin 
widths are determined.

Ben

Attachment: hist.pdf
Description: Adobe PDF document



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