Re: About diagonal matrices

[John W. Eaton]

On 22-Feb-2009, Jaroslav Hajek wrote:

| The situation is really analogous. To say it differently, it's as if
| you did a part of the calculation symbolically; therefore, the invalid
| numerical value (which a NaN is) does not demonstrate itself.

OK, I see the point, but it still seems somewhat bad that a NaN can
disappear from a calcuation.

In any case, at this point I don't think it makes sense to hold up the
release for this issue.

jwe