[Octave-bug-tracker] [bug #54490] Order of evaluation in assignment expression

[anonymous]

Follow-up Comment #4, bug #54490 (project octave):

As I inspected the source, the parser when parsing the expression:


[x(a)]=y


creates an instance of _tree_multi_assignment_ class and for


x(a)=y


it creates an instance of _tree_simple_assignment_ class.
Now I'm curious to know how does MATLAB evaluate this:
 

function [x y]=test1()
        global k;
        k = 1;
        x = rand;
        y = rand;
end

global k;

k = 2;
a = cell;
[a{1:k}] = test1();
a


and this:


function [x y]=test2()
        disp(nargout)
        global k;
        k = 1;
        x = rand;
        y = rand;
end

global k;

k = 2;
a = cell;
[a{1:k}] = test2();
a


The problem is that when MATLAB begins to run a function that has multiple
outputs it should know, before entring the function, the number of outputs
requested or *nargout*. I think Octave takes the correct way that first
evaluates the left hand side and then the right hand side.

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