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From: | Phil Holmes |
Subject: | Re: baseMoment and beatStructure |
Date: | Fri, 13 Mar 2015 16:21:15 -0000 |
To: <address@hidden> Sent: Friday, March 13, 2015 4:06 PM Subject: baseMoment and beatStructure
I have been banging my head against the wall with this for the longest time.What I'm looking for with this is 3 16th notes single beam 3 more 16th notes single beam and 3 more 16th notes. What I get is 12 16th notes beamed together. r2. \tuplet 3/2 8 { \set Timing.baseMoment = #(ly:make-moment 1/8) \set Timing.beatStructure = #'(3 3 3) bes,16 ( c d ees f g a bes c d ees e f g a bes f d ) } I've tried many, many combinations and have never found one that accomplishes what I'd like. Maybe I'm using the wrong constructs?
Have another look at the NR:"If a beamExceptions rule is defined for the time signature in force, that rule alone is used to determine the beam placement; the values of baseMoment and beatStructure are ignored."
The default time signature is 4/4, which does have a beamExceptions rule: as the NR says, you have to clear that rule.
--Phil Holmes
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