Re: tie problem

[Maurí­cio]

  I believe this approach could also work properly:

<< <c d g>1\arpeggio~ \\ s1 >> | << <c d g>1\fermata \\ {r2 r4 b'32 (c d 
e f g a b)} >>

i.e., a second "space" voice is added to the first compass. However, 
don't take it as example of good style, since I've just started to learn 
Lily.

  Best,
  Maurício


Rainer Hahnekamp wrote:
> Hi Kieren,
>
> thank you very much vor answer. (...)
>
> Greetings,
> Rainer
>
> Kieren MacMillan wrote: (...)

> > > I've following code:
> > > <c d g>1\arpeggio ~ | << <c d g>1\fermata \\ {r2 r4 b'32 (c d e f g
> > > a b)} >>
> > >
> > > According to the documentation the two "<c d g>" should be tied.
> > > Unfortunately this is not the case.


> > (...)
> > using \new Voice -- this ensures that anything before
> > the \new Voice command is considered part of the Voice that existed
> > before the <<>> block began, and so the tie knows where to terminate.
> >
> > Does that make sense?
> > Or, at the very least, does it explain why you're seeing what you're
> > seeing?  =)
> >
> > Best regards,
> > Kieren.